Finalization TimeoutException
The Problem of Finalizer
相信很多 Android 开发者都见过像这样的 TimeoutException :
java.util.concurrent.TimeoutException: android.content.res.AssetManager.finalize() timed out after 10 seconds
at android.content.res.AssetManager.destroy(Native Method)
at android.content.res.AssetManager.finalize(AssetManager.java:603)
at java.lang.Daemons$FinalizerDaemon.doFinalize(Daemons.java:187)
at java.lang.Daemons$FinalizerDaemon.run(Daemons.java:170)
at java.lang.Thread.run(Thread.java:856)
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通过查看 AOSP 源码,我们很容易就能定位到异常发生在 Daemons$FinalizerWatchdogDaemon.finalizerTimedOut :
private static void finalizerTimedOut(Object object) {
// The current object has exceeded the finalization deadline; abort!
String message = object.getClass().getName() + ".finalize() timed out after "
+ VMRuntime.getRuntime().getFinalizerTimeoutMs() / 1000 + " seconds";
Exception syntheticException = new TimeoutException(message);
// We use the stack from where finalize() was running to show where it was stuck.
syntheticException.setStackTrace(FinalizerDaemon.INSTANCE.getStackTrace());
// Send SIGQUIT to get native stack traces.
try {
Os.kill(Os.getpid(), OsConstants.SIGQUIT);
// Sleep a few seconds to let the stack traces print.
Thread.sleep(5000);
} catch (Exception e) {
System.logE("failed to send SIGQUIT", e);
} catch (OutOfMemoryError ignored) {
// May occur while trying to allocate the exception.
}
// Ideally, we'd want to do this if this Thread had no handler to dispatch to.
// Unfortunately, it's extremely to messy to query whether a given Thread has *some*
// handler to dispatch to, either via a handler set on itself, via its ThreadGroup
// object or via the defaultUncaughtExceptionHandler.
//
// As an approximation, we log by hand an exit if there's no pre-exception handler nor
// a default uncaught exception handler.
//
// Note that this condition will only ever be hit by ART host tests and standalone
// dalvikvm invocations. All zygote forked process *will* have a pre-handler set
// in RuntimeInit and they cannot subsequently override it.
if (Thread.getUncaughtExceptionPreHandler() == null &&
Thread.getDefaultUncaughtExceptionHandler() == null) {
// If we have no handler, log and exit.
System.logE(message, syntheticException);
System.exit(2);
}
// Otherwise call the handler to do crash reporting.
// We don't just throw because we're not the thread that
// timed out; we're the thread that detected it.
Thread.currentThread().dispatchUncaughtException(syntheticException);
}
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从源码里,我们可以看到 finalizerTimedOut 会抛出 UncaughtException,那为什么会调到这儿呢?让我们继续看源码:
@Override public void runInternal() {
while (isRunning()) {
if (!sleepUntilNeeded()) {
// We have been interrupted, need to see if this daemon has been stopped.
continue;
}
final Object finalizing = waitForFinalization();
if (finalizing != null && !VMDebug.isDebuggerConnected()) {
finalizerTimedOut(finalizing);
break;
}
}
}
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原来,FinalizerWatchdogDaemon 会异步等待 Finalization 结束:
private Object waitForFinalization() {
if (finalizerTimeoutMs == 0) {
finalizerTimeoutMs = VMRuntime.getRuntime().getFinalizerTimeoutMs();
// Temporary app backward compatibility. Remove eventually.
MAX_FINALIZE_NANOS = NANOS_PER_MILLI * finalizerTimeoutMs;
}
long startCount = FinalizerDaemon.INSTANCE.progressCounter.get();
// Avoid remembering object being finalized, so as not to keep it alive.
if (!sleepForMillis(finalizerTimeoutMs)) {
// Don't report possibly spurious timeout if we are interrupted.
return null;
}
if (getNeedToWork() && FinalizerDaemon.INSTANCE.progressCounter.get() == startCount) {
// We assume that only remove() and doFinalize() may take time comparable to
// the finalizer timeout.
// We observed neither the effect of the gotoSleep() nor the increment preceding a
// later wakeUp. Any remove() call by the FinalizerDaemon during our sleep
// interval must have been followed by a wakeUp call before we checked needToWork.
// But then we would have seen the counter increment. Thus there cannot have
// been such a remove() call.
// The FinalizerDaemon must not have progressed (from either the beginning or the
// last progressCounter increment) to either the next increment or gotoSleep()
// call. Thus we must have taken essentially the whole finalizerTimeoutMs in a
// single doFinalize() call. Thus it's OK to time out. finalizingObject was set
// just before the counter increment, which preceded the doFinalize call. Thus we
// are guaranteed to get the correct finalizing value below, unless doFinalize()
// just finished as we were timing out, in which case we may get null or a later
// one. In this last case, we are very likely to discard it below.
Object finalizing = FinalizerDaemon.INSTANCE.finalizingObject;
sleepForMillis(500);
// Recheck to make it even less likely we report the wrong finalizing object in
// the case which a very slow finalization just finished as we were timing out.
if (getNeedToWork()
&& FinalizerDaemon.INSTANCE.progressCounter.get() == startCount) {
return finalizing;
}
}
return null;
}
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看到这里,我想大家已经弄明白,为什么会抛出 TimeoutException 了,这是因为 FinalizerWatchdogDaemon 会等待 FinalizerDaemon.doFinalize() 的结果,如果在 MAX_FINALIZE_NANOS 时间之内没有完成,就会抛出 TimeoutException。
The Root Cause
从源码中我们可以看到,Daemons 启了 4 个 Daemon 线程:
public final class Daemons {
private static final Daemon[] DAEMONS = new Daemon[] {
HeapTaskDaemon.INSTANCE,
ReferenceQueueDaemon.INSTANCE,
FinalizerDaemon.INSTANCE,
FinalizerWatchdogDaemon.INSTANCE,
};
public static void start() {
for (Daemon daemon : DAEMONS) {
daemon.start();
}
}
}
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HeapTaskDaemon
HeapTaskDaemon 用来启动用于处理 GC 相关的任务,如:Heap Trimming, Heap Transition 以及 Concurrent GC,详见:task_processor.hopen in new window
ReferenceQueueDaemon
ReferenceQueueDaemon 负责将 FinalizerReference (重写了 finalize() 方法的类在实例化的时候,会被 FinalizerReference 引用,当该实例具有且仅有 FinalizerReference 引用它时,则认为该对象适合被 GC 回收)入队到 ReferenceQueue 中
FinalizerDaemon
FinalizerDaemon 负责在 GC 被触发时,执行被 FinalizerReference 引用的对象的 finalize 方法
FinalizerWatchdogDaemon
FinalizerWatchdogDaemon 顾名思义,它就是 Finalizer 的「看门狗」,一旦在规定的时间之内,没有给它「喂骨头」,则认为 Finalizer 过程被阻塞了,它就会抛异常了,而 FinalizerDaemon 就是给它「喂骨头」的线程。
How To Solve It?
了解了 4 个 Daemon 线程的作用,那这个问题就好办了,有人提出把超时时间 MAX_FINALIZE_NANOS 设置长一些不就行了?比如:Integer.MAX_VALUE,看起来貌似这是最简单的办法,真的可行吗?让我们来看看源码:
public final class Daemons {
// This used to be final. IT IS NOW ONLY WRITTEN. We now update it when we look at the command
// line argument, for the benefit of mis-behaved apps that might read it. SLATED FOR REMOVAL.
// There is no reason to use this: Finalizers should not rely on the value. If a finalizer takes
// appreciable time, the work should be done elsewhere. Based on disassembly of Daemons.class,
// the value is effectively inlined, so changing the field never did have an effect.
// DO NOT USE. FOR ANYTHING. THIS WILL BE REMOVED SHORTLY.
@UnsupportedAppUsage
private static long MAX_FINALIZE_NANOS = 10L * 1000 * NANOS_PER_MILLI;
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从源码中,我们可以看到 MAX_FINALIZE_NANOS 是一个常量值,根据我们对 JVM 规范的了解,常量是一个立即数,已经被编码进指令中,即使运行时修改它,也不会有任何作用。
Booster 的解决方案是解决抛出异常的「看门狗」—— 在应用启动后,停掉 FinalizerWatchdogDaemon 线程,这样做对于 APP 来说,并没有什么实质性的影响:
public static void kill() {
new Thread(new Runnable() {
@Override
public void run() {
for (int retry = 0; isFinalizerWatchdogDaemonExists() && retry < MAX_RETRY_TIMES; retry++) {
try {
final Class clazz = Class.forName("java.lang.Daemons$FinalizerWatchdogDaemon");
final Field field = clazz.getDeclaredField("INSTANCE");
field.setAccessible(true);
final Object watchdog = field.get(null);
try {
final Field thread = clazz.getSuperclass().getDeclaredField("thread");
thread.setAccessible(true);
thread.set(watchdog, null);
} catch (final Throwable t) {
Log.e(TAG, "Clearing reference of thread `FinalizerWatchdogDaemon` failed", t);
try {
final Method method = clazz.getSuperclass().getDeclaredMethod("stop");
method.setAccessible(true);
method.invoke(watchdog);
} catch (final Throwable e) {
Log.e(TAG, "Interrupting thread `FinalizerWatchdogDaemon` failed", e);
break;
}
}
try {
Thread.sleep(THREAD_SLEEP_TIME);
} catch (final InterruptedException ignore) {
}
} catch (final Throwable t) {
Log.e(TAG, "Killing thread `FinalizerWatchdogDaemon` failed", t);
break;
}
}
if (isFinalizerWatchdogDaemonExists()) {
Log.e(TAG, "Killing thread `FinalizerWatchdogDaemon` failed");
} else {
Log.i(TAG, "Thread `FinalizerWatchdogDaemon` does not exist");
}
}
}, "FinalizerWatchdogDaemonKiller").start();
}
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Getting Started
修复 FinalizerDaemon
导致的 TimeoutException 只需要引入 booster-transform-finalizer-watchdog-daemonopen in new window 即可,如下所示:
buildscript {
ext {
kotlin_version = "1.5.31"
booster_version = "4.16.3"
}
repositories {
mavenCentral()
google()
}
dependencies {
classpath 'com.android.tools.build:gradle:3.5.0'
classpath "org.jetbrains.kotlin:kotlin-gradle-plugin:$kotlin_version"
classpath "com.didiglobal.booster:booster-gradle-plugin:$booster_version"
/* 👇👇👇👇 引用这个模块 👇👇👇👇 */
classpath "com.didiglobal.booster:booster-transform-finalizer-watchdog-daemon:$booster_version"
}
}
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